document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=815252>Question 815252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi tutor, \r<BR>\n" );
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document.write( "Can you help me prove the following trig identity:\r<BR>\n" );
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document.write( "Prove that sin ^2(x)+tan ^2(x)=sec^2(x)-cos^2(x)\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #490816 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=490816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  sin ^2(x)+tan ^2(x)=sec^2(x)-cos^2(x)\r<BR>\n" );
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document.write( "sin^2x = 1-cos^2x\r<BR>\n" );
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document.write( "tan^2x=sec^2x-1\r<BR>\n" );
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document.write( "LHS\r<BR>\n" );
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document.write( "sin ^2(x)+tan ^2(x)\r<BR>\n" );
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document.write( "substitute <BR>\n" );
document.write( "1-cos^2x+sec^2x-1<BR>\n" );
document.write( "=sec^2x-cos^2x\r<BR>\n" );
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document.write( "=RHS\r<BR>\n" );
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document.write( " </SPAN>\n" );
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