document.write( "Question 815264: I want to find out how to solve this question:\r
\n" ); document.write( "\n" ); document.write( "\"How many liters of a 10% solution of acid should mixed with 60% solution of acid to obtain a 20 liters of 50% solution?\"\r
\n" ); document.write( "\n" ); document.write( "Do I need to use 2 variables? And will my set up of the equation be \"x(.10)+y(.60)=20(.50)\" ? or are there errors that must be corrected?
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Algebra.Com's Answer #490804 by Alan3354(69443)\"\" \"About 
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\"How many liters of a 10% solution of acid should mixed with 60% solution of acid to obtain a 20 liters of 50% solution?\"\r
\n" ); document.write( "\n" ); document.write( "Do I need to use 2 variables? And will my set up of the equation be
\n" ); document.write( "\"x(.10)+y(.60)=20(.50)\" ? or are there errors that must be corrected?
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\n" ); document.write( "x(.10)+y(.60)=20(.50)
\n" ); document.write( "That's one equation, for the amount of acid.
\n" ); document.write( "x + y = 20 is the other.
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