document.write( "Question 809582: Find the radius of a circle with equation \r
\n" ); document.write( "\n" ); document.write( "x^2 - 6x + y^2 + 10y = 2 \n" ); document.write( "

Algebra.Com's Answer #490799 by plastery(3) $\"\"$ $\"About$

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$\"%28x-x%5B0%5D%29%5E2%2B%28y-y%5B0%5D%29%5E2=r%5E2\"$ this is the standard equation for a circonference with center at point ( $\"x%5B0%5D\"$ , $\"y%5B0%5D\"$ ) and radius r.
\n" ); document.write( "So let's try to put the given equation in standard form.
\n" ); document.write( " $\"x%5E2-6x%2By%5E2%2B10y=2\"$
\n" ); document.write( " $\"x%5E2-2%2A3%2Ax%2By%5E2-2%2A%28-5%29%2Ay=2\"$
\n" ); document.write( " $\"x%5E2-2%2A3%2Ax%2B3%5E2-3%5E2%2By%5E2-2%2A%28-5%29%2Ay%2B%28-5%29%5E2-%28-5%29%5E2=2\"$
\n" ); document.write( " $\"x%5E2-2%2A3%2Ax%2B3%5E2%2By%5E2-2%2A%28-5%29%2Ay%2B%28-5%29%5E2=2%2B3%5E2%2B%28-5%29%5E2\"$
\n" ); document.write( " $\"%28x-3%29%5E2%2B%28y-%28-5%29%29%5E2=2%2B3%5E2%2B%28-5%29%5E2\"$
\n" ); document.write( " $\"%28x-3%29%5E2%2B%28y-%28-5%29%29%5E2=2%2B9%2B25\"$
\n" ); document.write( " $\"%28x-3%29%5E2%2B%28y-%28-5%29%29%5E2=36\"$
\n" ); document.write( " $\"%28x-3%29%5E2%2B%28y-%28-5%29%29%5E2=6%5E2\"$
\n" ); document.write( "Therefore the given equation stands for a circonference with center in (3,-5) and radius 6 \n" ); document.write( "

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