document.write( "Question 815208: 1 Jane and Peter leave their home traveling in opposite directions on a straight road. Peter drives 15 miles per hour faster than Jane. After three hours, they are 225 miles apart. Find Peter’s rate and Jane’s rate.\r
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document.write( "2 Noya drives into the city to buy a computer program. Due to traffic conditions, she averages only 15 mi/h. On her drive home, she averages 35 mi/h. If her total travel time is 2 hours, how long did it take her to drive to the computer store?
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Algebra.Com's Answer #490788 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Think of this as Jane standing still and \n" ); document.write( "Peter moving away from her at the sum of their speeds \n" ); document.write( "Let Jane's speed in mi/hr = \n" ); document.write( "Peter's speed = \n" ); document.write( "---------------------- \n" ); document.write( "When Peter is 225 mi from Jane: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Jane's rate is 30 mi/hr \n" ); document.write( "Peter's rate is 45 mi/hr \n" ); document.write( "-------------------------------------- \n" ); document.write( "Average speed = ( total distance ) / ( total time ) \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------ \n" ); document.write( "Going back home: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "also: \n" ); document.write( " \n" ); document.write( "By substitution: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Her time going to the store was 1 hr 24 min \n" ); document.write( " |