document.write( "Question 815181: Dear Team\r
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document.write( "can you please help to get answers on these 2 questions?\r
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document.write( "1.Select the option for “?” that continues the pattern in each question
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document.write( "2, 7, 26, 101, 400, ?\r
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document.write( "2.Select the option for “?” that continues the pattern in each question
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document.write( "7, 21, 8, 72, 9, ? \n" );
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Algebra.Com's Answer #490754 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! I see a pattern for the first set in which you take the given number and multiply by 4 and subtract 1, then multiply by 4 subtract 2, multiply by 4 subtract 3, mult by 4 and subtract 4, etc. Starting with 2, multiply by 4 subtract 1 giving you 7. Take 7, multiply by 4 and subtract 2 giving you 26. Mult 26 times 4 and subtract 3 giving you 101. Multi by 4 subtract 4 giving you 400. Next would be multiply by 4 and subtract 5 giving 1595.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For the second pattern, I'm not sure. You might try starting with 7 *3 = 21. Next, take 8*3^2= 72. Next, take 9*3^3=243. This might be a stretch, but it's all I can think of.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Happy Thanksgiving!! Please see my website for FREE math explanations, and practice tests. See www.mathinlivingcolor.com.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje, Retired \n" ); document.write( "Seminole State College of Florida\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |