document.write( "Question 68965: A total of $10,000 is invested in two funds paying 5% and 7% annual interest. The combined interest is $630. How much of the $10,000 is invested in each fund? \n" ); document.write( "
Algebra.Com's Answer #49075 by checkley75(3666)\"\" \"About 
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.07x+.05(10000-x)=630
\n" ); document.write( ".07x+500-.05x=630
\n" ); document.write( ".02x=630-500
\n" ); document.write( ".02x=130
\n" ); document.write( "x=130/.02
\n" ); document.write( "x=6500 invested @7%.
\n" ); document.write( "thus the remaining 10000-6500=3500 invested @5%.
\n" ); document.write( "proof
\n" ); document.write( ".07*6500+.05*3500=630
\n" ); document.write( "455+175=630
\n" ); document.write( "630=630
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