document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=815070>Question 815070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What rate of interest is required to triple an investment in 12 years if the interest is compounded continuously? Use A+Pe^rt. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #490730 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=490730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What rate of interest is required to triple an investment in 12 years if the interest is compounded continuously? Use A+Pe^rt.<BR>\n" );
document.write( "***<BR>\n" );
document.write( "A=Pe^rt, P=initial investment, r=rate of interest, A=amt after t-years<BR>\n" );
document.write( "A/P=3=e^rt<BR>\n" );
document.write( "rtlne=ln3<BR>\n" );
document.write( "lne=1<BR>\n" );
document.write( "rt=ln3<BR>\n" );
document.write( "r=ln3/12&#8776;0.09155<BR>\n" );
document.write( "rate of interest required=9.2% (rounded) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );