document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68968>Question 68968</A>: <I><SPAN STYLE=\"word-break: break-all;\"> =Yesterday, Manuel's electronics store sold several radios at $18.50 each and a few blank cassettes at $1 each. The difference in the number of these items sold was eight. If the total sales of radios and cassettes for the day were $265.00, how many of each item were sold? Use the addition method of solving systems. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49073 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1850x+100y=26500 <BR>\n" );
document.write( "x-y=8 multiply this equation by 100 & add.<BR>\n" );
document.write( "100x-100y=800<BR>\n" );
document.write( "1850x+100y=26500<BR>\n" );
document.write( "------------------------------------------------<BR>\n" );
document.write( "1950x=27300<BR>\n" );
document.write( "x=27300/1950<BR>\n" );
document.write( "x=14 radios were sold.<BR>\n" );
document.write( "therefore there were 14-y=8 or -y=8-14 or y=6 cassettes sold.<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "14*1850+6*100=26500<BR>\n" );
document.write( "25900+600=26500<BR>\n" );
document.write( "26500=26500 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );