document.write( "Question 814874: The rate of a small aircraft in calm air is 125mph if the wind is currently blowing south at a rate of 10mph how far north can a pilot fly the plane and return it with 2hrs? \n" ); document.write( "
Algebra.Com's Answer #490622 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
The rate of a small aircraft in calm air is 125mph if the wind is currently blowing south at a rate of 10mph how far north can a pilot fly the plane and return it with 2hrs?
\n" ); document.write( ":
\n" ); document.write( "let d = one way dist to return in 2hrs
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "time up + time back = 2hrs
\n" ); document.write( "\"d%2F%28%28125-10%29%29\" + \"d%2F%28%28125%2B10%29%29\" = 2
\n" ); document.write( ":
\n" ); document.write( "\"d%2F115\" + \"d%2F135\" = 2
\n" ); document.write( "multiply by
\n" ); document.write( "115*135, resulting in
\n" ); document.write( "135d + 115d = (135)(115)*2
\n" ); document.write( "250d = 31050
\n" ); document.write( "d = 31050/250
\n" ); document.write( "d = 124.2 mi north
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the time each way
\n" ); document.write( "124.2/115 = 1.08 hrs
\n" ); document.write( "124.2/135 = .92
\n" ); document.write( "--------------------
\n" ); document.write( "total time: 2 hrs
\n" ); document.write( "
\n" );