document.write( "Question 814903: In what ratio must a peanut costing $5.71 per kg be mixed with a peanut costing
\n" ); document.write( " $ 8.5 per kg so that a profit of 20% is made by selling the mixture at $9 per kg?
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Algebra.Com's Answer #490593 by josgarithmetic(39617)\"\" \"About 
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You want 9 dollars per kg to be 20% more than the price for the mixture.
\n" ); document.write( "Some p mixture price before profit;
\n" ); document.write( "\"9=1.20%2Ap\"
\n" ); document.write( "\"p=9%2F1.20\"
\n" ); document.write( "\"highlight%28p=7.5%29\" dollars per kilogram, price of the mixture BEFORE profit.\r
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\n" ); document.write( "\n" ); document.write( "The rest of the solution is just a standard two part mixture problem in which you treat prices like concentrations.\r
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\n" ); document.write( "\n" ); document.write( "u is kg of the cheap peanuts and v is the kg of the expensive peanuts, and you can choose 100 kg. peanut mixture.\r
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\n" ); document.write( "\n" ); document.write( "\"%285.71u%2B8.5v%29%2F100=7.5\" and \"u%2Bv=100\"
\n" ); document.write( "Solve for u and v.
\n" ); document.write( "The choice of 100 for the kilograms of the mixture was just arbitrary; you could choose a different value. What you were asked was for the ratio between u and v.
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