document.write( "Question 814829: Please help me sketch the following function by determining the critical points as follows: f(x)=sqrt(x-4): the domain and intercepts \n" ); document.write( "
Algebra.Com's Answer #490560 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Not sure if it is called a critical point, but \"x%3E=4\" is a requirement in Real Numbers for the domain of f(x). The far-left point is the one which intersects the x axis, at (4,0). In other way of saying, \"f%284%29=0\". No other axis intercepts.\r
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\n" ); document.write( "\n" ); document.write( "Hopefully, a better explanation:
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\n" ); document.write( "DOMAIN: What value are acceptable for x?
\n" ); document.write( "Square Root function for real numbers must accept positive values for zero. Negative values are not acceptable.\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=sqrt%28x-4%29\" must have \"x-4%3E=0\" which means \"x%3E=0%2B4\" or \"x%3E=4\".
\n" ); document.write( "This means, the DOMAIN of f(x) is \"highlight%28x%3E=4%29\".\r
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\n" ); document.write( "\n" ); document.write( "Checking for intercepts, at x=0, what is f(x)?
\n" ); document.write( "\"f%280%29=sqrt%280-4%29\", NOT acceptable because 0 is not in the domain of f(x). Recall, we just found that the domain of f(x) is \"x%3E=4\", and \"0%3C4\", so x cannot be 0. This means, f(x) will not cross the y-axis.
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\n" ); document.write( "What about f(x)=0? What would x be for this?
\n" ); document.write( "\"f%28x%29=0=sqrt%28x-4%29\"
\n" ); document.write( "\"0=sqrt%28x-4%29\"
\n" ); document.write( "Square both sides,
\n" ); document.write( "\"0=x-4\"
\n" ); document.write( "\"x=4\"
\n" ); document.write( "This is the point, (4,0) as the x-intercept.\r
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\n" ); document.write( "\n" ); document.write( "Your will recognize the equation as half of a parabola with horizontal axis of symmetry:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-2%2C12%2C-2%2C7%2Csqrt%28x-4%29%29\"
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