document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68906>Question 68906</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Geometry. If the sides of a square are decreased by 2cmm the area is <BR>\n" );
document.write( "decreased by 36cm^2. What were the dimensions of the original square?''.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #49049 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=49049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Geometry. If the sides of a square are decreased by 2cmm the area is <BR>\n" );
document.write( "decreased by 36cm^2. What were the dimensions of the original square?''.\r<BR>\n" );
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document.write( "Let x=length of each side of the original square<BR>\n" );
document.write( "x^2= area of original square\r<BR>\n" );
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document.write( "Then x-2 =length of each side of the smaller square\r<BR>\n" );
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document.write( "(x-2)^2= area of smaller square\r<BR>\n" );
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document.write( "Now we are told that x^2-(x-2)^2=36 cm^2  clear parens\r<BR>\n" );
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document.write( "x^2-x^2+4x-4=36  add 4 from both sides\r<BR>\n" );
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document.write( "4x=40\r<BR>\n" );
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document.write( "x=10 cm------------------------------length of sides of original square\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "10^2-8^2=36 <BR>\n" );
document.write( "100-64=36<BR>\n" );
document.write( "36=36\r<BR>\n" );
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document.write( "Hope this helps-----ptaylor<BR>\n" );
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