document.write( "Question 68904: This problem is on a quadratic equation assignment and I do not know how to set it up.\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 3 cm more than 2 times its width. If the area of the rectangle is 99 cm^2, find both dimensions of the rectangle to the nearest thousandth.\r
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Algebra.Com's Answer #49046 by rmromero(383)\"\" \"About 
You can put this solution on YOUR website!

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document.write( "What is asked in the problem?
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document.write( "Find the lenght and the width of the rectangle to the nearest thousandth.\r
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document.write( "Given:
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document.write( "Lenght of a rectangle is 3cm more than 2 times its width.
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document.write( "the area of the rectangle is 99 cm^2.\r
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document.write( "Representation:
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document.write( "Let     x = width of the rectangle
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document.write( "   2x + 3 = length of the rectangle\r
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document.write( "Write and equation: 
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document.write( "Remember that the Area of the rectangle = Length times the width\r
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document.write( " A = (2x + 3)(x)
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document.write( "99 = 2x^2 + 3x
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document.write( " 0 = 2x^2 + 3x - 99\r
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document.write( "Factor : Use Quadratic Formula
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document.write( "    ax^2 + bx + c = 0, a = 2, b = 3, c= -99\r
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document.write( "       \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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document.write( "       \"x+=+%28-3+%2B-+sqrt%28+3%5E2-4%2A2%2A%2899%29%29%29%2F%282%2A2%29+\" 
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document.write( "       \"x+=+%28-3+%2B-+sqrt%28+9+%2B+792+%29%29%2F%284%29\" 
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document.write( "       \"x+=+%28-3+%2B-+sqrt%28+801%29%29%2F%284%29\" 
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document.write( "       \"x+=+%28-3%2F4%29+%2B-+%28sqrt%28+801%29%2F4%29+\"\r
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document.write( "x = 6.325   and     x = -7.825\r
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document.write( "no lenght or width that is negative so disregard x = -7.825\r
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document.write( "width of the rectangle = 6.325 cm   \r
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document.write( "lenght = 2x + 3 
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document.write( "       = 2(6.325) + 3 
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document.write( "       = 12.65 + 3
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document.write( "       = 15.65 cm\r
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