document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=814668>Question 814668</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, I really need help with this problem...A bucket full of water has a leak. The bucket loses 71ml of water every 5 minutes. Let t represent the number of minutes since the bucket started leaking.<BR>\n" );
document.write( "A. As the number of minutes since the bucket started leaking increases from 13 to 29 minutes, what is the corresponding change in the volume of the water in the bucket?<BR>\n" );
document.write( "B. By how much will the volume of the water in the bucket change when the number of minutes since the bucket started leaking changes by one minute? <BR>\n" );
document.write( "C. As the volume of water in the bucket decreases from 60 ml to 23 ml, what is the corresponding change in the number of minutes since the bucket started leaking? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #490441 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=490441\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, find the rate of water loss per minute.<BR>\n" );
document.write( "71ml in 5 minutes means we loose 71/5 ml  each minute.\r<BR>\n" );
document.write( "\n" );
document.write( "A. Going from 13 minutes to 29 minutes takes ( 29-13 = 16 ) minutes.<BR>\n" );
document.write( "   16 minutes times 71/5 gives us (16 * 71/5) or 227.2 ml lost<BR>\n" );
document.write( "B. See above<BR>\n" );
document.write( "C. Going from 60 to 23 is a loss of 37.<BR>\n" );
document.write( "   Set t = time<BR>\n" );
document.write( "   71/5 * t = amount lost<BR>\n" );
document.write( "   71/5 * t = 37<BR>\n" );
document.write( "Multiply each side by 5/71<BR>\n" );
document.write( "          t = 37 * (5/71)<BR>\n" );
document.write( "          t = 2.605 minutes<BR>\n" );
document.write( " </SPAN>\n" );
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