document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=814686>Question 814686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I cannot come up with a formula to solve this.  If lean hamburger purchased at $1.89 but loses 10% weight during cooking--and regular hamburger costs $1.09 but loses 30% weight during cooking...what would have to be the purchase price of the lean meat in order to make it of equal value to the regular?  Thank you!\r<BR>\n" );
document.write( "\n" );
document.write( "Rebecca </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #490431 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=490431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = lean price, y = cost<BR>\n" );
document.write( "y=(1-0.10)x   cost is (100%-10%) times x<BR>\n" );
document.write( "y=0.90x\r<BR>\n" );
document.write( "\n" );
document.write( "for regular hamburger<BR>\n" );
document.write( "y=(1-0.30)1.09   cost is (100%-30%) times $1.09<BR>\n" );
document.write( "y= 0.70*1.09<BR>\n" );
document.write( "y= 0.763\r<BR>\n" );
document.write( "\n" );
document.write( "So when 0.90x = 0.763 lean and regular would have the same value.<BR>\n" );
document.write( "            x= 0.763/0.90<BR>\n" );
document.write( "            x=0.8477 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );