document.write( "Question 814647: you have 17 coins in pennies, nickels, and dimes in your pockets. the value of the coins is $0.47. There are four times the number of pennies as nickels. How many of each type of coin do you have? \n" ); document.write( "
Algebra.Com's Answer #490423 by LinnW(1048)\"\" \"About 
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Set p = number of pennies
\n" ); document.write( " n = number of nickles
\n" ); document.write( " d = number of dimes
\n" ); document.write( "p(1) + n(5) + d(10) = 47
\n" ); document.write( "that is, the number of pennies x 1 cent + number nickles x 5 cents
\n" ); document.write( " + number of dimes x ten cents equals 47 cents
\n" ); document.write( "p = 4n
\n" ); document.write( "p + n + d = 17\r
\n" ); document.write( "\n" ); document.write( "Substituting 4n for p in the above
\n" ); document.write( "4n + n + d = 17
\n" ); document.write( "5n + d = 17
\n" ); document.write( "Subtract 5n from each side
\n" ); document.write( " d = 17 - 5n
\n" ); document.write( "We will now substitute 4n for p and ( 17-5n ) for d in
\n" ); document.write( "the equation
\n" ); document.write( "p(1) + n(5) + d(10) = 47\r
\n" ); document.write( "\n" ); document.write( "4n(1) +n(5) + (17-5n)(10) = 47
\n" ); document.write( " 9n + 170 - 50n = 47
\n" ); document.write( " -41n + 170 = 47
\n" ); document.write( "Subtract 170 from each side
\n" ); document.write( " -41n = 47 - 170
\n" ); document.write( " -41n = -123
\n" ); document.write( "Divide each side by -41
\n" ); document.write( " n = 3
\n" ); document.write( "Since p = 4n
\n" ); document.write( " p = 4(3)
\n" ); document.write( " p = 12
\n" ); document.write( "Since p + n + d = 17
\n" ); document.write( " 12 + 3 + d = 17
\n" ); document.write( " 15 + d = 17
\n" ); document.write( " d = 2
\n" ); document.write( "So we have 12 pennies, 3 nickles and 2 dimes
\n" ); document.write( " 12 + 3(5) + 2(10) ?= 47
\n" ); document.write( " 12 + 15 + 20 ?= 47
\n" ); document.write( "Looks like it checks out.
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