document.write( "Question 814647: you have 17 coins in pennies, nickels, and dimes in your pockets. the value of the coins is $0.47. There are four times the number of pennies as nickels. How many of each type of coin do you have? \n" ); document.write( "
Algebra.Com's Answer #490423 by LinnW(1048)![]() ![]() You can put this solution on YOUR website! Set p = number of pennies \n" ); document.write( " n = number of nickles \n" ); document.write( " d = number of dimes \n" ); document.write( "p(1) + n(5) + d(10) = 47 \n" ); document.write( "that is, the number of pennies x 1 cent + number nickles x 5 cents \n" ); document.write( " + number of dimes x ten cents equals 47 cents \n" ); document.write( "p = 4n \n" ); document.write( "p + n + d = 17\r \n" ); document.write( "\n" ); document.write( "Substituting 4n for p in the above \n" ); document.write( "4n + n + d = 17 \n" ); document.write( "5n + d = 17 \n" ); document.write( "Subtract 5n from each side \n" ); document.write( " d = 17 - 5n \n" ); document.write( "We will now substitute 4n for p and ( 17-5n ) for d in \n" ); document.write( "the equation \n" ); document.write( "p(1) + n(5) + d(10) = 47\r \n" ); document.write( "\n" ); document.write( "4n(1) +n(5) + (17-5n)(10) = 47 \n" ); document.write( " 9n + 170 - 50n = 47 \n" ); document.write( " -41n + 170 = 47 \n" ); document.write( "Subtract 170 from each side \n" ); document.write( " -41n = 47 - 170 \n" ); document.write( " -41n = -123 \n" ); document.write( "Divide each side by -41 \n" ); document.write( " n = 3 \n" ); document.write( "Since p = 4n \n" ); document.write( " p = 4(3) \n" ); document.write( " p = 12 \n" ); document.write( "Since p + n + d = 17 \n" ); document.write( " 12 + 3 + d = 17 \n" ); document.write( " 15 + d = 17 \n" ); document.write( " d = 2 \n" ); document.write( "So we have 12 pennies, 3 nickles and 2 dimes \n" ); document.write( " 12 + 3(5) + 2(10) ?= 47 \n" ); document.write( " 12 + 15 + 20 ?= 47 \n" ); document.write( "Looks like it checks out. \n" ); document.write( " |