document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=814648>Question 814648</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on this word problem please.\r<BR>\n" );
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document.write( "burts burger shack sold 495 burgers today. the number sold with cheese was 1/2 the number of burgers sold without cheese. how many of each kind of burger were sold? \r<BR>\n" );
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document.write( "thank you : ) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #490419 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=490419\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Set c = number of burgers with cheese<BR>\n" );
document.write( "Set w = number of burgers without cheese\r<BR>\n" );
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document.write( "c = 1/2 * w   One half as many have cheese\r<BR>\n" );
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document.write( "w + c = 495   The number without plus the number with equal 495\r<BR>\n" );
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document.write( "Notice that we can substitute ( 1/2 * w ) for c in the above equation<BR>\n" );
document.write( "w + ( 1/2 * w ) = 495<BR>\n" );
document.write( "1 1/2 * w = 495<BR>\n" );
document.write( "or <BR>\n" );
document.write( "3/2 w = 495<BR>\n" );
document.write( "Multiply each side by 2/3<BR>\n" );
document.write( "(2/3)(3/2) * w = 495 * (2/3)<BR>\n" );
document.write( "           w = 990/3<BR>\n" );
document.write( "           w = 330<BR>\n" );
document.write( "Since w + c = 495<BR>\n" );
document.write( "      390 + c = 495<BR>\n" );
document.write( "          c = 165<BR>\n" );
document.write( "So we have 165 with cheese and 390 without. </SPAN>\n" );
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