Algebra.Com's Answer #49041 by rmromero(383)  You can put this solution on YOUR website! It takes a boat 4 hours to travel 56 miles down a river, and 3 hours longer to make the return trip. Find the speed of the current. \n" );
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document.write( "What is asked in the problem? \n" );
document.write( "Find the speed of the current?\r \n" );
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document.write( "Given: \n" );
document.write( "It takes a boat 4 hours to travel 56 miles down the river \n" );
document.write( "3 hours longer to make a return trip.\r \n" );
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document.write( "Representation: \n" );
document.write( "Let x = speed of the boat in still water \n" );
document.write( " y = speed of the current\r \n" );
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document.write( "Make a table for the information given: \n" );
document.write( " r t = d \n" );
document.write( "Downstream x+y 4 = 56 \n" );
document.write( "Upstream x-y 4+3 = 56\r \n" );
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document.write( "Write an Equation: \n" );
document.write( "4 (x + y) = 56 \n" );
document.write( "7 (x - y) = 56\r \n" );
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document.write( " x + y = 14 \n" );
document.write( " x - y = 8 \n" );
document.write( " __________\r \n" );
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document.write( " 2x = 22 \n" );
document.write( " x = 11 miles/hour <<<<< speed of the boat in still water\r \n" );
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document.write( " x + y = 14 \n" );
document.write( "11 + y = 14 \n" );
document.write( " y = 3 miles/hour <<<<<<<<< speed of the current\r \n" );
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document.write( "Checking: \n" );
document.write( "4 (x + y) = 56 , x = 11, y = 3 \n" );
document.write( "4(11 + 3) = 56 \n" );
document.write( " 4(14) = 56 \n" );
document.write( " 56 = 56 ----------->> True\r \n" );
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document.write( "7 (x - y) = 56, x = 11, y = 3 \n" );
document.write( "7(11 - 3) = 56 \n" );
document.write( " 7 (8) = 56 \n" );
document.write( " 56 = 56 ------->> True\r \n" );
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