document.write( "Question 814569: The length of a rectangle is 13 centimeters less than three times its width. Its area is 56 square centimeters. Find the dimensions of the rectangle \n" ); document.write( "
Algebra.Com's Answer #490409 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi,
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document.write( "The length of a rectangle is 13 centimeters less than three times its width.
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document.write( "Let x represent the width and (3x-13) the length
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document.write( "Question states***Its area is 56 square centimeters.
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document.write( "  A = \"%283x-13%29%2Ax+=+56+cm%5E2\"
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document.write( "Solving for x
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document.write( "  3x^2 - 13x - 56 =0
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document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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document.write( "\"x+=+%2813+%2B-+sqrt%28+841+%29%29%2F%286%29+\"  
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document.write( "\"x+=+%2813+%2B-+29%29%2F%286%29+\"  
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document.write( "  x = 7   0r  x = -16/6 (tossing out negative solution for unit measure)
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document.write( "Width is 7cm  and length is 8cm   (3x-13)    \n" );
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