document.write( "Question 814532: Sara begins the race with a pace of 8 miles/hr. but gets tired after 15 min. and slows down to 4 miles/hr.
\n" ); document.write( "Katy runs a steady pace of 5 miles/hr. the entire race.
\n" ); document.write( "At what distance will katy pass sara?
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Algebra.Com's Answer #490351 by josgarithmetic(39618)\"\" \"About 
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Recognize two time periods: The first quarter of hour, and AFTER the first quarter of hour. The \"AFTER\" part is a variable time, call it h.\r
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\n" ); document.write( "\n" ); document.write( "Sara: \"8%2A%281%2F4%29%2B4%2Ah+=+d\" for some unknown distance d, based on the unknown time h.\r
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\n" ); document.write( "\n" ); document.write( "Katy: The same steady speed the whole race, but for ALL of \"%281%2F4%29%2Bh\" hours of time.
\n" ); document.write( "\"5%281%2F4%2Bh%29+=+d\"\r
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\n" ); document.write( "\n" ); document.write( "When Sara and Katy reach the same distance, their \"d\" is the same, and we can equation them and solve for h. Once h is found, use either equation to compute d. Start this with \"highlight%288%281%2F4%29%2B4h=5%281%2F4%2Bh%29%29\"
\n" ); document.write( "\"2%2B4h=5%2F4%2B5h\"
\n" ); document.write( "\"2=5%2F4%2Bh\"
\n" ); document.write( "\"h=2-5%2F4=2-1.25=highlight%280.75%29\"
\n" ); document.write( "This is three-quarters of an hour, or 45 minutes.\r
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\n" ); document.write( "\n" ); document.write( "You still need to find the distance.
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