document.write( "Question 814538: x pounds of candy valued at $3.50 per pound is mixed with y pounds of candy valued at $4.30 per pound to produce 10 pounds of a mixture selling for $4 per pound. Find x and y, the number of pounds of each type. I've tried this several different ways and can't see to do it right. This is due tomorrow and I'm freaking out about what I'm doing wrong. \n" ); document.write( "

Algebra.Com's Answer #490346 by mananth(16946) $\"\"$ $\"About$

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x= quantity candy I
\n" ); document.write( "y= quantity candy II
\n" ); document.write( "
\n" ); document.write( "1.00 x + 1.00 y = 10.00 .............1
\n" ); document.write( "Total value
\n" ); document.write( "3.50 x + 4.30 y = 40.00 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -4.30
\n" ); document.write( "Multiply (2) by 1.00
\n" ); document.write( "-4.30 x -4.30 y = -43.00
\n" ); document.write( "3.50 x + 4.30 y = 40.00
\n" ); document.write( "Add the two equations
\n" ); document.write( "-0.80 x = -3.00
\n" ); document.write( "/ -0.80
\n" ); document.write( "x = 3.75
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1.00 x + 1.00 y = 10.00
\n" ); document.write( "3.75 + y = 10.00
\n" ); document.write( " y = 10.00 -3 3/4
\n" ); document.write( " y = 6.25
\n" ); document.write( " y = 6.25
\n" ); document.write( "x= 3.75 quantity candy I
\n" ); document.write( "y= 6.25 quantity candy II
\n" ); document.write( "m.ananth@hotmail.ca \r
\n" ); document.write( "\n" ); document.write( "cool \n" ); document.write( "

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