document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=814443>Question 814443</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is exactly how it is typed:<BR>\n" );
document.write( "A number is 6 greater than half another number. If the sum of the numbers is 21, find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #490316 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=490316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The description is ambiguous. The first part seems to be saying, 6+(1/2)n, if one of the numbers is m and the other is n.\r<BR>\n" );
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document.write( "Letting m and n be the numbers,<BR>\n" );
document.write( "m=6+(1/2)n and m+n=21.<BR>\n" );
document.write( "Substitute for m in the second equation.<BR>\n" );
document.write( "(6+(1/2)n)+n=21<BR>\n" );
document.write( "6+n/2+n=21<BR>\n" );
document.write( "(3/2)n=21-6<BR>\n" );
document.write( "(3/2)n=15<BR>\n" );
document.write( "n=(2/3)15<BR>\n" );
document.write( "n=10 and this means m=11. </SPAN>\n" );
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