document.write( "Question 68894: factor completly using the perfect cube factorization formula\r
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document.write( "y^3+a^3=(y+a)(y^2-ay+a^2)\r
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document.write( "8y^3+1 \n" );
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Algebra.Com's Answer #49029 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! y^3+a^3=(y+a)(y^2-ay+a^2)\r \n" ); document.write( "\n" ); document.write( "8y^3+1 \n" ); document.write( "=(2y)^3 + 1^3 \n" ); document.write( "=(2y+1)((2y)^2-2y+1) \n" ); document.write( "=(2y+1)(4y^2-2y+1) \n" ); document.write( "---------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |