document.write( "Question 814330: the perimeter of a rectangle lot is 350ft. the length of the lot is 10ft. more than twice the width. find the deminsion of the lot? \n" ); document.write( "

Algebra.Com's Answer #490259 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "P = 350ft
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document.write( "the length of the lot is 10ft more than twice the width 
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document.write( "Let x and (2x+10) represent the width and length
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document.write( " 2(2x+10) + 2x = 350ft
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document.write( "  6x = 330ft
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document.write( "   x = 55ft, the width.  The length is 120ft   (2x+10)
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document.write( "CHECKING our Answer***
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