document.write( "Question 814330: the perimeter of a rectangle lot is 350ft. the length of the lot is 10ft. more than twice the width. find the deminsion of the lot? \n" ); document.write( "
Algebra.Com's Answer #490257 by TimothyLamb(4379)\"\" \"About 
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2L + 2w = 350
\n" ); document.write( "L = 2w + 10
\n" ); document.write( "---
\n" ); document.write( "2L + 2w = 350
\n" ); document.write( "2(2w + 10) + 2w = 350
\n" ); document.write( "4w + 20 + 2w = 350
\n" ); document.write( "6w = 330
\n" ); document.write( "---
\n" ); document.write( "w = 55
\n" ); document.write( "L = 2w + 10
\n" ); document.write( "L = 110 + 10
\n" ); document.write( "L = 120
\n" ); document.write( "---
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