document.write( "Question 68874: A passenger train's speed is 60 mi/h, and a freight train's speed is 40 mi/h. The passenger train travels the same distance in 1.5 h less time than te freight train. How long does each train take to make the trip? \n" ); document.write( "

Algebra.Com's Answer #49025 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
A passenger train's speed is 60 mi/h, and a freight train's speed is 40 mi/h. The passenger train travels the same distance in 1.5 h less time than te freight train. How long does each train take to make the trip?
\n" ); document.write( ":
\n" ); document.write( "The trains travel the same distance so we can make a distance equation from that:
\n" ); document.write( "let t = time for the pass train
\n" ); document.write( ":
\n" ); document.write( "let (t+1.5) = time for the freight
\n" ); document.write( ":
\n" ); document.write( "d = speed * time:
\n" ); document.write( ":
\n" ); document.write( "Pass dist = Freight dist
\n" ); document.write( "60t = 40(t+1.5)
\n" ); document.write( "60t = 40t + 60
\n" ); document.write( "60t - 40t = 60
\n" ); document.write( "20t = 60
\n" ); document.write( "t = 60/20
\n" ); document.write( "t = 3 hrs for the passenger train; 3 + 1.5 = 4.5 hrs for freight
\n" ); document.write( ":
\n" ); document.write( "Check by finding the distance traveled of each train:
\n" ); document.write( "3(60) = 4.5(40)
\n" ); document.write( "180 = 180 \n" ); document.write( "

\n" );