document.write( "Question 68873: $5000.00 was invested in 2 different bonds. One bond yielded 5% in one year and the other yielded 6% in one year. The total yield was $280.00.
\n" ); document.write( "How much was invested in each bond?\r
\n" ); document.write( "\n" ); document.write( "I originally set up the problem as such:
\n" ); document.write( ".05A+.06B=280
\n" ); document.write( "I don't know what steps to take from there. I know what the answer is but do not understand how to figure on paper. .05A=280-.06B Other than plug in numbers and guess, I do not understand how to do.\r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #49021 by rmromero(383)\"\" \"About 
You can put this solution on YOUR website!
What is asked in the problem?
\n" ); document.write( "How much was invested in each bond?
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\n" ); document.write( "Given :
\n" ); document.write( "$5000 was invested in 2 different bonds
\n" ); document.write( "one yields 5% in one year
\n" ); document.write( "the other yielded 6% in one year
\n" ); document.write( "The total yield was $280.00
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\n" ); document.write( "Representation:
\n" ); document.write( "A = investment which yield 5% in dollars
\n" ); document.write( "B = investment which yield 6% in dollars
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\n" ); document.write( "Write an Equation. Translate the given sentences to mathematical sentence.
\n" ); document.write( "A + B = $5000
\n" ); document.write( "0.05A + 0.06B = $280.00 <-- it is better if you multiply 100 each term so that you will not deal with decimal later on.
\n" ); document.write( "0.05A + 0.06B = $280.00 is the same as 5A + 6B = 28000
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\n" ); document.write( "We can now use Substitution method to solve for the variable of the two equations.
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\n" ); document.write( "Here are the Steps using Substition method
\n" ); document.write( "1. In either equation, solve for one variable in terms of the other.
\n" ); document.write( "A + B = $5000
\n" ); document.write( "A = -B + 5000
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\n" ); document.write( "2. Substitute for that variable in the other equation. Solve.
\n" ); document.write( "5A + 6B = 28000
\n" ); document.write( "5(-B+5000) + 6B = 28000
\n" ); document.write( "-5B - 25000 + 6B = 28000
\n" ); document.write( "B = $ 3000 <<<<<<<< investment which yield 6% in dollars
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\n" ); document.write( "3. Substitute the result from step 2 in either equation. Solve for the other variable.
\n" ); document.write( "A + B = $5000, B = $3000
\n" ); document.write( "A + 3000 = 5000
\n" ); document.write( "A = $ 2000 <<<<<< investment which yield 5% in dollars
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\n" ); document.write( "4. Check the solution in both original equations.
\n" ); document.write( "A + B = $5000, A = $2000, B = $3000
\n" ); document.write( "2000 + 3000 = 5000
\n" ); document.write( "5000 = 5000 --------->> True
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\n" ); document.write( "5A + 6B = 28000, A = $2000, B = $3000
\n" ); document.write( "5(2000) + 6(3000) = 28000
\n" ); document.write( "10000 + 18000 = 28000
\n" ); document.write( "28000 = 28000 ----------->> True\r
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Therefore $2,000 was invested at 5% and $3,000 was invested at 6%
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