document.write( "Question 814229: 1.) An angle's measure is 18 more than 3 times its complement. Find the measure of the angle.\r
\n" ); document.write( "\n" ); document.write( "2.) The supplement of an angle is 4 times as large as the angle's complement. Find the measure of the angle.\r
\n" ); document.write( "\n" ); document.write( "Thank you for helping.
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Algebra.Com's Answer #490177 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "1)An angle's measure is 18° more than 3 times its complement.
\n" ); document.write( "Let x represent the angle and (90° - x) represent its complement
\n" ); document.write( "Question states******
\n" ); document.write( " x = 3(90°-x) + 18°
\n" ); document.write( "Solving for x
\n" ); document.write( " 4x = 288°
\n" ); document.write( " x = 72°, the angle, its complement is 18°
\n" ); document.write( "CHECKING our Answer*****
\n" ); document.write( " \"72+=+3%2A18+%2B+18\"
\n" ); document.write( "2)The supplement of an angle is 4 times as large as the angle's complement.
\n" ); document.write( "Let x represent the angle, (90° - x)its complement & (180°-x) its supplement
\n" ); document.write( "Question states***
\n" ); document.write( " (18°0-x) = 4(90°-x)
\n" ); document.write( "Solving for x
\n" ); document.write( " 3x = 180°
\n" ); document.write( " x = 60° the angle, complement is 30° and supplement is 120°
\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " \"120+=+4%2A30\" \n" ); document.write( "
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