document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=813851>Question 813851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Garrett averages 60 mph and Gordon averages 65 mph. Gordon couldn't find his car keys, so he lest the office to travel to a meeting in another state 15 minutes after Garrett. How long will it be until Gordon catches up to Garrett?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #489995 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=489995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Garrett averages 60 mph and Gordon averages 65 mph. Gordon couldn't find his car keys, so he lest the office to travel to a meeting in another state 15 minutes after Garrett. How long will it be until Gordon catches up to Garrett? <BR>\n" );
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document.write( "In 15 minutes, Garrett is 15 miles away (60 mi/hr * 1/4 hr)<BR>\n" );
document.write( "Gordon \"gains on him\" at 5 mi/hr (65-60)<BR>\n" );
document.write( "15/5 = 3 hours to catch up.<BR>\n" );
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document.write( "Gordon \"gains on him\" at 5 mi/hr (65-60)<BR>\n" );
document.write( "Gordon's speed with respect to Garrett is 5 mi/hr = \"gains on\"<BR>\n" );
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