document.write( "Question 813830: a certain two digit number is equal to 9 times the sum of its digits. If 63 were subtracted from the number, the digits would be reversed. Find the number. \n" ); document.write( "

Algebra.Com's Answer #489978 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "two digit number (xy) is equal to 9 times the sum of its digits.****
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document.write( " 10x + y = 9(x+y)  0r   x-8y = 0 ****
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document.write( "If 63 were subtracted from the number, the digits would be reversed.***
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document.write( " 10x + y - 63 = 10y + x  0r  9x -9y = 63  0r  x-y = 7\r
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document.write( " x-8y = 0
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document.write( " x-y = 7    |Subtracting 2nd EQ from 1st EQ
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document.write( " -7y = -7
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document.write( "   y = 1   and x = 8    (x-y = 7  or  x = y + 7)
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document.write( "Number is 81 
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document.write( "CHECKING our Answer***
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document.write( "& 81 - 63 = 18
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