document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68834>Question 68834</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Directions: Solve each of the following quadratic equations.\r<BR>\n" );
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document.write( "Problem# 24\r<BR>\n" );
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document.write( "4x^2 = 13x +12\r<BR>\n" );
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document.write( "Directions: Solve the following problem<BR>\n" );
document.write( "Problem# 48\r<BR>\n" );
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document.write( "Geometry. If the sides of a square are decreased by 2cmm the area is decreased by 36cm^2. What were the dimensions of the original square? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48996 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48996\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4x^2=13x+12<BR>\n" );
document.write( "4x^2-13x-12=0<BR>\n" );
document.write( "(4x-3)(x+4)=0<BR>\n" );
document.write( "4x-3=0<BR>\n" );
document.write( "4x=3<BR>\n" );
document.write( "x=3/4 answer<BR>\n" );
document.write( "x+4=0<BR>\n" );
document.write( "x=-4 answer </SPAN>\n" );
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