document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68856>Question 68856</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the substitution method to solve the linear system\r<BR>\n" );
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document.write( "x+y=12<BR>\n" );
document.write( "x+3/2y=3/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48995 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=12<BR>\n" );
document.write( "x=12-y now replace x by (12-y) in the other equation thus:<BR>\n" );
document.write( "(12-y)+3/2y=3/2<BR>\n" );
document.write( "12-y+3/2y=3/2<BR>\n" );
document.write( "-y+1.5y=1.5-12<BR>\n" );
document.write( ".5y=-10.5<BR>\n" );
document.write( "y=-10.5/.5<BR>\n" );
document.write( "y=-21 answer.<BR>\n" );
document.write( "now substitute 21 for y and solve for x thus:<BR>\n" );
document.write( "x-21=12<BR>\n" );
document.write( "x=12+21<BR>\n" );
document.write( "x=33 answer<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "33+3/2*-21=3/2<BR>\n" );
document.write( "33-63/2=3/2<BR>\n" );
document.write( "33-31.5=1.5<BR>\n" );
document.write( "1.5=1.5 </SPAN>\n" );
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