document.write( "Question 813747: Hello, I was wondering if you could explain how to Write the equation of a line parallel to the given line but passing through the given point.
\n" ); document.write( "y=-2x-4; (1,3)? so far I have Y=-2x-4; (1, 3)
\n" ); document.write( "m= 1, (1, 3)
\n" ); document.write( "y-y1=m(x-x1)
\n" ); document.write( "y-3=1(x-1)
\n" ); document.write( "y-3=x-1
\n" ); document.write( "y=x+4
\n" ); document.write( "I am not sure if I have done this right or not. \r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #489920 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Line y=-2x-4, want line parallel to it, passing through (1,3).\r
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\n" ); document.write( "\n" ); document.write( "Given line is in slope-intercept form, indicating slope is -2. The slope of the line we want is also \"-2\".\r
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\n" ); document.write( "\n" ); document.write( "You have chose to continue the solution using Point-Slope form for a line, so I will do so also.\r
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\n" ); document.write( "\n" ); document.write( "You already know that m is for slope. Your point (\"x%5B1%5D\",\"y%5B1%5D\") is the point (1,3). You must KNOW now that m=-2. Substitute and simplify:\r
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\n" ); document.write( "\n" ); document.write( "\"y-3=-2%28x-1%29\"
\n" ); document.write( "\"y-3=-2x%2B2\"
\n" ); document.write( "\"y=-2x%2B2%2B3\"
\n" ); document.write( "\"highlight%28y=-2x%2B5%29\"---------Your Answer.\r
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\n" ); document.write( "\n" ); document.write( "PARALLEL, PARALLEL, PARALLEL, PARALLEL,... Same Slope!
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