document.write( "Question 813735: The number of trout in a breeding pond is given by, 1400/1+5e^-0.09t where t is the number of months that have passed since the pond was stocked with trout.\r
\n" ); document.write( "\n" ); document.write( "How many trout were in the pond immediately after it was stocked?
\n" ); document.write( "How many trout were in the pond 1 year after it was stocked?
\n" ); document.write( "what will happen to the trout population as t increases without bound?
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Algebra.Com's Answer #489919 by ankor@dixie-net.com(22740)\"\" \"About 
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The number of trout in a breeding pond is given by, Assume it's:
\n" ); document.write( "f(t) = \"1400%2F%281%2B5e%5E%28-0.09t%29%29\"
\n" ); document.write( " where t is the number of months that have passed since the pond was stocked with trout.
\n" ); document.write( ":
\n" ); document.write( "How many trout were in the pond immediately after it was stocked?
\n" ); document.write( "Then t=0, e^0 = 1, therefore
\n" ); document.write( "f(t) = \"1400%2F6\"
\n" ); document.write( "f(t) ~ 233 trout
\n" ); document.write( ":
\n" ); document.write( "How many trout were in the pond 1 year after it was stocked?
\n" ); document.write( "f(t) = \"1400%2F%281%2B5e%5E%28-0.09%2A12%29%29\"
\n" ); document.write( "f(t) = \"1400%2F%281%2B5%28.34%29%29\"
\n" ); document.write( "f(t) = \"1400%2F2.7\"
\n" ); document.write( "f(t) = 519 trout
\n" ); document.write( ":
\n" ); document.write( "what will happen to the trout population as t increases without bound?
\n" ); document.write( "Eventually 5e becomes so close to 0, it will level off at around 1400 trout,
\n" ); document.write( "t = 100 months = 1399 trout
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