document.write( "Question 813735: The number of trout in a breeding pond is given by, 1400/1+5e^-0.09t where t is the number of months that have passed since the pond was stocked with trout.\r
\n" );
document.write( "\n" );
document.write( "How many trout were in the pond immediately after it was stocked?
\n" );
document.write( "How many trout were in the pond 1 year after it was stocked?
\n" );
document.write( "what will happen to the trout population as t increases without bound? \n" );
document.write( "
Algebra.Com's Answer #489919 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The number of trout in a breeding pond is given by, Assume it's: \n" ); document.write( "f(t) = \n" ); document.write( " where t is the number of months that have passed since the pond was stocked with trout. \n" ); document.write( ": \n" ); document.write( "How many trout were in the pond immediately after it was stocked? \n" ); document.write( "Then t=0, e^0 = 1, therefore \n" ); document.write( "f(t) = \n" ); document.write( "f(t) ~ 233 trout \n" ); document.write( ": \n" ); document.write( "How many trout were in the pond 1 year after it was stocked? \n" ); document.write( "f(t) = \n" ); document.write( "f(t) = \n" ); document.write( "f(t) = \n" ); document.write( "f(t) = 519 trout \n" ); document.write( ": \n" ); document.write( "what will happen to the trout population as t increases without bound? \n" ); document.write( "Eventually 5e becomes so close to 0, it will level off at around 1400 trout, \n" ); document.write( "t = 100 months = 1399 trout \n" ); document.write( " |