document.write( "Question 68816: Suppose that you have entered a 15 - mile biathlon that consists of a run and a bicycle race. During your run, your average velocity is 7 miles per hour and during your swim, your average velocity is 2 miles per hour. You finish the race in 2.5 hours. What is the length of the swim? What is the distance of the run? \n" ); document.write( "
Algebra.Com's Answer #48991 by ankor@dixie-net.com(22740)\"\" \"About 
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Suppose that you have entered a 15 - mile biathlon that consists of a run and a bicycle race. During your run, your average velocity is 7 miles per hour and during your swim, your average velocity is 2 miles per hour. You finish the race in 2.5 hours. What is the length of the swim? What is the distance of the run?
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\n" ); document.write( "Let d = distance of the swim:
\n" ); document.write( "Then (15-d) = distance of the bike run
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\n" ); document.write( "Time = Dist/speed
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\n" ); document.write( "Swim time + Bike time = 2.5 hrs
\n" ); document.write( "\"d%2F2+%2B+%28%2815-d%29%29%2F7\" = 2.5
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\n" ); document.write( "Multiply equation by 14 to get rid of the denominators:
\n" ); document.write( "7d + 2(15-d) = 14(2.5)
\n" ); document.write( "7d + 30 - 2d = 35
\n" ); document.write( "7d - 2d = 35 - 30
\n" ); document.write( "5d = 5
\n" ); document.write( "d = 1 mile swim; and a 14 mile bike ride
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\n" ); document.write( "Check it using the distance: 1/2 + 14/7 = 2.5 hrs\r
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