document.write( "Question 813578: A boat is traveling 12 mph on a compass bearing of 180 degrees. There is a current of four mph flowing from east to west. What is the actual speed and direction of the boat relative to dry land? \n" ); document.write( "
Algebra.Com's Answer #489847 by TimothyLamb(4379)\"\" \"About 
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use vector velocities:
\n" ); document.write( "b: magnitude = 12, direction = 180 degrees
\n" ); document.write( "w: magnitude = 4, direction = 270 degrees
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\n" ); document.write( "we want the vector sum:
\n" ); document.write( "v = b + w
\n" ); document.write( "---
\n" ); document.write( "because the vectors are perpendicular, we can use the pythagorean theorem for the magnitude of v:
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\n" ); document.write( "magnitude of v:
\n" ); document.write( "M(v) = sqrt( bb + ww )
\n" ); document.write( "M(v) = sqrt( 144 + 16 )
\n" ); document.write( "M(v) = 12.649111
\n" ); document.write( "---
\n" ); document.write( "direction of v:
\n" ); document.write( "for the direction of v we need the small angle (A) of the right triangle:
\n" ); document.write( "tan(A) = opp/adj = 4/12 = 1/3
\n" ); document.write( "A = arctan(1/3) = 18.434949 degrees
\n" ); document.write( "D(v) = 180 + 18.434949 = 198.434949 degrees
\n" ); document.write( "---
\n" ); document.write( "Answer:
\n" ); document.write( "from dry land the boat will appear to be moving on a bearing and speed of:
\n" ); document.write( "198.4 degrees at 12.7 mph
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