document.write( "Question 813591: from 4 feet above the ground, Maya throws a ball upward with the velocity of 18 feet per second. The height h(t) of the ball t seconds after Maya throws the ball given by h(t)=-16t^2+18+4. Find the maximum height reached by the ball and the time that this height is reached \n" ); document.write( "
Algebra.Com's Answer #489798 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
Your equation is wrong
\n" ); document.write( "h(t)=-16t^2+18+4
\n" ); document.write( "should be
\n" ); document.write( "h(t)=-16t^2+18t+4
\n" ); document.write( "You want the vertex
\n" ); document.write( "x will be t
\n" ); document.write( "and y will be h(t)
\n" ); document.write( "vertex | (9/16, 145/16)=(0.5625, 9.0625)
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