document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=813580>Question 813580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area enclosed by the curve, y=25- x^2 and the straight line, y=x+13<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #489792 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=489792\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the area enclosed by the curve, y=25- x^2 and the straight line, y=x+13<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "The 2 points of intersection are at x = -4 and x = 3.<BR>\n" );
document.write( "y=25- x^2<BR>\n" );
document.write( "INT(x) = 25x - x^3/3<BR>\n" );
document.write( "INT(3) = 75 - 9 = 66<BR>\n" );
document.write( "INT(-4) = -100 + 64/3 = -236/3<BR>\n" );
document.write( "Area under parabola to x-axis = 66 + 236/3 = 434/3<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "Area under line = 87.5<BR>\n" );
document.write( "--> 343/6 sq units </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );