document.write( "Question 813527: Alicia needs to get to work at 8am. On Tuesday, she drove to work at an average speed of 40 miles per hour, and arrived 3 minutes late. On Wednesday, she left 10 minutes earlier and took the same route. Due to reduced traffic, she managed to drive to work at an average speed of 45 miles per hour. If she arrived 15 minutes early, what is the distance (in miles) of the route to work? \n" ); document.write( "

Algebra.Com's Answer #489745 by lwsshak3(11628) $\"\"$ $\"About$

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Alicia needs to get to work at 8am. On Tuesday, she drove to work at an average speed of 40 miles per hour, and arrived 3 minutes late. On Wednesday, she left 10 minutes earlier and took the same route. Due to reduced traffic, she managed to drive to work at an average speed of 45 miles per hour. If she arrived 15 minutes early, what is the distance (in miles) of the route to
\n" ); document.write( "***
\n" ); document.write( "let x=distance of route
\n" ); document.write( "distance/speed=travel time
\n" ); document.write( "Difference in travel times between Tuesday's and Wednesday's trips:
\n" ); document.write( "3 min late Tuesday and 5 min early on Wednesday=8 min
\n" ); document.write( " $\"x%2F40-x%2F45=8%2F60\"$
\n" ); document.write( "45x-40x=40*45*8/60
\n" ); document.write( "5x=240
\n" ); document.write( "x=48
\n" ); document.write( "distance of route=48 mi \n" ); document.write( "

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