document.write( "Question 813420: Sketch the titration curve (volume versus pH) for the addition of 0.50 M NaOH to 20.0 mL of 0.20 M HCl.\r
\n" );
document.write( "\n" );
document.write( "Mark clearly the starting point and the half-equivalence point and the pH and calculate their values.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #489740 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! The equivalence point volume would be when the moles of added NaOH and already-present HCl match.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Titrant volumes less than 8 ml. will keep HCl in excess and the pH will be directly from the excess HCl. Titrant volumes larger than 8 ml. will ensure that NaOH is in excess and so pH will be based on the NaOH present in excess.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your volume increments to use for data point calculations could be 1 mililiter increments, but you might choose a different increment, or more than just one size increment. \n" ); document.write( " |