document.write( "Question 813420: Sketch the titration curve (volume versus pH) for the addition of 0.50 M NaOH to 20.0 mL of 0.20 M HCl.\r
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Algebra.Com's Answer #489740 by josgarithmetic(39617)\"\" \"About 
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The equivalence point volume would be when the moles of added NaOH and already-present HCl match.\r
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\n" ); document.write( "\n" ); document.write( "\"0.5v=0.2%2A20\"
\n" ); document.write( "\"v=0.2%2A20%2F0.5\"
\n" ); document.write( "\"v=4%2F0.5=4%2A2=8\"
\n" ); document.write( "\"highlight%28v=8%29\" ml.\r
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\n" ); document.write( "\n" ); document.write( "Titrant volumes less than 8 ml. will keep HCl in excess and the pH will be directly from the excess HCl. Titrant volumes larger than 8 ml. will ensure that NaOH is in excess and so pH will be based on the NaOH present in excess.\r
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\n" ); document.write( "\n" ); document.write( "Your volume increments to use for data point calculations could be 1 mililiter increments, but you might choose a different increment, or more than just one size increment.
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