document.write( "Question 813413: A factory produces bicycles at a rate of 100+0.2t^2-0.7t bicycles per week ( in weeks). How many bicycles were produced from day 8 to 21? \n" ); document.write( "
Algebra.Com's Answer #489732 by TimothyLamb(4379)\"\" \"About 
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100 + 0.2t^2 - 0.7t = b(t) number of bicycles per week (t = weeks)
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\n" ); document.write( "days 8 to 21 correspond to the full 2nd and 3rd weeks, so t=2 and t=3
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\n" ); document.write( "b(2) = 100 + 0.2t^2 - 0.7t
\n" ); document.write( "b(2) = 100 + 0.2(4) - 0.7(2)
\n" ); document.write( "b(2) = 100 + 0.8 - 1.4
\n" ); document.write( "b(2) = 100 - 0.6
\n" ); document.write( "b(2) = 99.4
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\n" ); document.write( "b(3) = 100 + 0.2t^2 - 0.7t
\n" ); document.write( "b(3) = 100 + 0.2(9) - 0.7(3)
\n" ); document.write( "b(3) = 100 + 1.8 - 2.1
\n" ); document.write( "b(3) = 100 - 0.3
\n" ); document.write( "b(3) = 99.7
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\n" ); document.write( "b(2) + b(3) = 99.4 + 99.7 = 199.1
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\n" ); document.write( "Answer:
\n" ); document.write( "How many bicycles were produced from day 8 to 21?
\n" ); document.write( "199 bikes were produced during the 2nd and 3rd weeks
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