document.write( "Question 813487: David is twice as old as his daughter. In 14 years, David's age will be three times what his daughter's age was 6 years ago. How old are they now? \n" ); document.write( "

Algebra.Com's Answer #489717 by TimothyLamb(4379) $\"\"$ $\"About$

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d = 2k
\n" ); document.write( "d + 14 = 3(k - 6)
\n" ); document.write( "---
\n" ); document.write( "d + 14 = 3(k - 6)
\n" ); document.write( "d + 14 = 3k - 18
\n" ); document.write( "2k + 14 = 3k - 18
\n" ); document.write( "---
\n" ); document.write( "kid = 32
\n" ); document.write( "dave = 64
\n" ); document.write( "---
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