document.write( "Question 813136: Find the vertex, focus, and directrix of the parabola.\r
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Algebra.Com's Answer #489696 by lwsshak3(11628)\"\" \"About 
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Find the vertex, focus, and directrix of the parabola.
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\n" ); document.write( "x-y^2+4y-2=0
\n" ); document.write( "y^2-4y=x-2
\n" ); document.write( "complete the square:
\n" ); document.write( "(y^2-4y+4)=x-2+4
\n" ); document.write( "(y-2)^2=(x+2)
\n" ); document.write( "This is a parabola that opens rightwards:
\n" ); document.write( "Its basic form of equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex.
\n" ); document.write( "vertex:(-2,2)
\n" ); document.write( "axis of symmetry:y=2
\n" ); document.write( "4p=1
\n" ); document.write( "p=1/4
\n" ); document.write( "focus:(-7/4,2)
\n" ); document.write( "directrix:(-9/4,2)
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