document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68788>Question 68788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a chemist wants to make a 10% solution of fertilizer. How much water and how much of a 30% solution should the chemist mix to get 30 L of a 10% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #48969 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=48969\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a chemist wants to make a 10% solution of fertilizer. How much water and how much of a 30% solution should the chemist mix to get 30 L of a 10% solution?<BR>\n" );
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document.write( "Let amount of 30% solution be \"x\" L ; amt. of active ingredient=0.30x L<BR>\n" );
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document.write( "Amt. of 0% solution is \"30-x\" L; amt. of active ingredient = 0(30-x)=0 L<BR>\n" );
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document.write( "Amt of mixture is 30 L ; amt of active ingredient = 0.10(30)= 3 L<BR>\n" );
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document.write( "EQUATION:<BR>\n" );
document.write( "active + active = active<BR>\n" );
document.write( "0.30x + 0 = 3<BR>\n" );
document.write( "x=10 L (He should add 10 L of 30% solution)<BR>\n" );
document.write( "30-x=20L (He should add 20 L of water)<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
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