document.write( "Question 813468: On my Precal 20 test there was this question:
\n" ); document.write( "Two numbers equal 32. Their reciprocals equal 1/6. What are the two numbers?
\n" ); document.write( "I came up with two equations:
\n" ); document.write( "X+Y=32 and of course 1/X+1/Y=1/6 but no matter what I do the question seems impossible.
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Algebra.Com's Answer #489682 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "x + y = 32\r
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\n" ); document.write( "\n" ); document.write( "y = 32 - x\r
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\n" ); document.write( "\n" ); document.write( "1/x + 1/y = 1/6\r
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\n" ); document.write( "\n" ); document.write( "1/x + 1/(32 - x) = 1/6\r
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\n" ); document.write( "\n" ); document.write( "6x(32-x) * [1/x + 1/(32 - x)] = 6x(32-x)*(1/6) ... multiply both sides by the LCD to clear out the fractions\r
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\n" ); document.write( "\n" ); document.write( "6(32-x) + 6x = x(32-x)\r
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\n" ); document.write( "\n" ); document.write( "192 - 6x + 6x = 32x - x^2\r
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\n" ); document.write( "\n" ); document.write( "192 = 32x - x^2\r
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\n" ); document.write( "\n" ); document.write( "0 = 32x - x^2 - 192\r
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\n" ); document.write( "\n" ); document.write( "32x - x^2 - 192 = 0\r
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\n" ); document.write( "\n" ); document.write( "-x^2 + 32x - 192 = 0\r
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\n" ); document.write( "\n" ); document.write( "-1*(-x^2 + 32x - 192) = -1*0\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 32x + 192 = 0\r
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\n" ); document.write( "\n" ); document.write( "(x-8)(x-24) = 0\r
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\n" ); document.write( "\n" ); document.write( "I'll let you finish up. Don't forget to check any possible answers you get.\r
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