document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=813329>Question 813329</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A farmer has 3000 feet of wire to enclose a rectangular field. He plans to fence the entire area and then subdivide it by running a perpendicular fence across the middle. Find the dimensions of the field that would enclose the maximum area . What is the maximum area?\r<BR>\n" );
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document.write( "Can you please help me out? Thanks so much in advance:) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #489641 by </B><A HREF=/tutors/aboutme.mpl?userid=TimothyLamb><B>TimothyLamb(4379)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TimothyLamb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TimothyLamb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=489641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = Lw<BR>\n" );
document.write( "P = 2L + 2w = 3000<BR>\n" );
document.write( "2L + 2w = 3000<BR>\n" );
document.write( "2L = 3000 - 2w<BR>\n" );
document.write( "L = 1500 - w<BR>\n" );
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document.write( "A = Lw<BR>\n" );
document.write( "A = (1500 - w)w<BR>\n" );
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document.write( "A(w) = -w^2 + 1500w + 0<BR>\n" );
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document.write( "the above quadratic function is represented by the quadratic equation in standard form, with a=-1, b=1500, and c=0<BR>\n" );
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document.write( "to find the maximum area A(w), plug this:<BR>\n" );
document.write( "-1 1500 0<BR>\n" );
document.write( "into this: https://sooeet.com/math/quadratic-equation-solver.php<BR>\n" );
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document.write( "Answer 1:<BR>\n" );
document.write( "the maximum point of the above quadratic equation is: ( w= 750, A(w)= 562500 )<BR>\n" );
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document.write( "so the maximum area that can be enclosed is: 562500 sq.ft<BR>\n" );
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document.write( "now, to find the L and w dimensions of the maximum area, remember this equation from above:<BR>\n" );
document.write( "A(w) = -w^2 + 1500w + 0<BR>\n" );
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document.write( "we used that equation to maximize Area, but as a side effect we also got w for the max area, from the max point of the quadratic equation ( w= 750, A(w)= 562500 )<BR>\n" );
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document.write( "Answer 2:<BR>\n" );
document.write( "w for maximum area = 750<BR>\n" );
document.write( "L for maximum area = 1500 - w = 1500 - 750 = 750<BR>\n" );
document.write( "so the maximum area has dims: w=750, L=750 feet<BR>\n" );
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document.write( "Solve and graph linear equations:<BR>\n" );
document.write( "https://sooeet.com/math/linear-equation-solver.php<BR>\n" );
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document.write( "Solve quadratic equations, quadratic formula:<BR>\n" );
document.write( "https://sooeet.com/math/quadratic-formula-solver.php<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Convert fractions, decimals, and percents:<BR>\n" );
document.write( "https://sooeet.com/math/fraction-decimal-percent.php<BR>\n" );
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document.write( "Calculate and graph the linear regression of any data set:<BR>\n" );
document.write( "https://sooeet.com/math/linear-regression.php </SPAN>\n" );
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