document.write( "Question 813352: please help:
\n" ); document.write( "show that there is at least one function to x^3+x=3 for x greater than 0. \n" ); document.write( "

Algebra.Com's Answer #489639 by htmentor(1343) $\"\"$ $\"About$

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I assume you mean there is at least one solution (zero) of the function for x>0?
\n" ); document.write( "To show that the function has a zero, we can use the intermediate value theorem.
\n" ); document.write( "This states that if a function f(x) is continuous and f(x) < 0 at a point a and f(x) > 0 at a point b,
\n" ); document.write( "then there must be a zero at some point, c, in between a and b.
\n" ); document.write( "x^3+x = 3 -> x^3+x-3
\n" ); document.write( "f(x) = x^3+x-3
\n" ); document.write( "f(1) = 1+1-3 = -1
\n" ); document.write( "f(2) = 8+2-3 = 9
\n" ); document.write( "This means that the function crosses zero on the interval (1,2)
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