document.write( "Question 813198: Solve.\r
\n" ); document.write( "\n" ); document.write( "x^2+y^2=97
\n" ); document.write( "xy=36\r
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Algebra.Com's Answer #489636 by richwmiller(17219)\"\" \"About 
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factors of 36
\n" ); document.write( "12 and 3 squares 144 is too much
\n" ); document.write( "9 and 4 81 and 16 97 is just right
\n" ); document.write( "6 and 6 36 and 36 72
\n" ); document.write( "x=36/y
\n" ); document.write( "(36/y)^2+y^2=97
\n" ); document.write( "1296/y^2+y^2=97
\n" ); document.write( "y^2-13y+36 = 0
\n" ); document.write( "(y-9) (y-4) = 0
\n" ); document.write( "y=9 and y=4\r
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