document.write( "Question 813344: Find the equation of a circle whose diameter has endpoints (4, -1) and (-6, 7).
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Algebra.Com's Answer #489597 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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\n" ); document.write( "circle whose diameter has endpoints (4, -1) and (-6, 7).
\n" ); document.write( "D = \"sqrt+%28%28x%5B1%5D-x%5B2%5D%29%5E2%2B%28y%5B1%5D-y%5B2%5D%29%5E2%29%29\"
\n" ); document.write( "D = \"sqrt+%28%2810%5E2%2B+%28-8%29%5E2%29%29+=+sqrt%28164%29+=+2sqrt%2841%29\"
\n" ); document.write( "r = \"sqrt%2841%29\"
\n" ); document.write( "Midpoint Pt(x,y): ( \"%28x%5B1%5D+%2B+x%5B2%5D%29%2F2\", \"%28y%5B1%5D+%2B+y%5B2%5D%29%2F2++%29\")\r
\n" ); document.write( "\n" ); document.write( "Midpoint Pt(x,y): (-2/2 , 6/2) 0r (-1,3)
\n" ); document.write( "Standard Form of an Equation of a Circle is \"%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2\"
\n" ); document.write( "where Pt(h,k) is the center and r is the radius
\n" ); document.write( "\"%28x%2B1%29%5E2+%2B+%28y-3%29%5E2+=+41\"
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