document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=813318>Question 813318</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If area of rectangle is 30cm2 and its perimeter is 22 cm  what will be lengths of its sides  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #489580 by </B><A HREF=/tutors/aboutme.mpl?userid=AlbertusK><B>AlbertusK(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AlbertusK><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=489580\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of rectangle = 30cm2.<BR>\n" );
document.write( "Perimeter of rectangle = 22 cm.\r<BR>\n" );
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document.write( "Assume that it's length is L and it's width is W.\r<BR>\n" );
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document.write( "So we can conclude that L.W = 30 and (2L+2W)=22 --> L+W=11.\r<BR>\n" );
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document.write( "It's just a simple linear problem. We have L = 11-W and just subtitute L for \r<BR>\n" );
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document.write( "L.W=30. So the result is (11-W).W = 30.\r<BR>\n" );
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document.write( "11W - W^2 - 30 = 0 --> W^2 - 11W + 30 = 0 --> (W-6)(W-5)=0.\r<BR>\n" );
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document.write( "So there are 2 possibilities for it's width namely 5 cm and 6 cm.\r<BR>\n" );
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document.write( "So there are also 2 possibilities for it's length namely 6cm and 5cm.\r<BR>\n" );
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document.write( "The answer is (L,W) = (6,5) and (5,6). </SPAN>\n" );
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